The necessary volume of $HCl$ $0.105M$ is $25.3ml$.
Work Step by Step
1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = C_2 * V_2$ $ 0.118* 22.5= 0.105 * V_2$ $ 2.655 = 0.105 * V_2$ $V_2 = 25.29$
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