## Chemistry: The Central Science (13th Edition)

The necessary volume of $HCl$ $0.105M$ is $25.3ml$.
1. Find the volume necessary for an equal number of moles: $C_1 * V_1 = C_2 * V_2$ $0.118* 22.5= 0.105 * V_2$ $2.655 = 0.105 * V_2$ $V_2 = 25.29$