Answer
The necessary volume of $HCl$ $0.105M$ is $25.3ml$.
Work Step by Step
1. Find the volume necessary for an equal number of moles:
$C_1 * V_1 = C_2 * V_2$
$ 0.118* 22.5= 0.105 * V_2$
$ 2.655 = 0.105 * V_2$
$V_2 = 25.29$
Chemistry: The Central Science (13th Edition)
by Brown, Theodore E.; LeMay, H. Eugene; Bursten, Bruce E.; Murphy, Catherine; Woodward, Patrick; Stoltzfus, Matthew E.
Published by
Prentice Hall
ISBN 10:
0321910419
ISBN 13:
978-0-32191-041-7
Chapter 17 - Additional Aspects of Aqueous Equilibria - Exercises - Page 769: 17.42b
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