## Chemistry: The Central Science (13th Edition)

- Write the reaction: $Ca(OH)_2(aq) + HClO_4(aq) -- \gt Ca^{2+}(aq) + Cl{O_4}^-(aq) + H_2O(l)$. - Analyzing the remaining compounds. $Ca^{2+}:$ Insignificant acid. $Cl{O_4}^-:$ Insignificant base. Therefore, there are no significant electrolytes remaining in the solution: Neutral pH: $pH = 7$