Answer
The necessary volume is $35ml$ of $0.0850M$ $NaOH$.
Work Step by Step
- Both are monoprotics acid and base.
1. Find the volume necessary for an equal number of moles:
$C_1 * V_1 = C_2 * V_2$
$ 0.085* 35= 0.085 * V_2$
$ 2.975 = 0.085 * V_2$
$V_2 = 35ml$
