Answer
The necessary volume of $HCl$ $0.105M$ is $41ml$.
Work Step by Step
1. Find the volume necessary for an equal number of moles:
$C_1 * V_1 = C_2 * V_2$
$ 0.095* 45= 0.105 * V_2$
$ 4.275 = 0.105 * V_2$
$V_2 = 40.71ml$
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