Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 17 - Additional Aspects of Aqueous Equilibria - Exercises - Page 769: 17.41a


Approximately 42.35ml.

Work Step by Step

Since NaOH is a strong base, and HNO3 is a strong acid, we can use this formula for a titration: $C_1 * V_1 = C_2*V_2$ $0.085 * V_1 = 0.09 * 0.04$ $V_1 = \frac{0.0036}{0.085}$ $V_1 \approx 4.235 \times 10^{-2} L \approx 42.35 ml $
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