# Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 86

$$1.67*10^{20} molecules$$

#### Work Step by Step

We know that one drop of water contains 1/20 g, which is .05 g. We know that the molar mass of water is 18.02 g/mol as well. This allows us to find: $$\frac{.05 g}{1}* \frac{1 mol}{18.02 g}* \frac{6.022*10^{23} molecules}{mol}\\=1.67*10^{20} molecules$$

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