## Chemistry: The Molecular Science (5th Edition)

We know that the given compound has a molar mass of 236.31 g/mol. Since we also know that there are .250 grams present in the sample, we obtain: $$\frac{1 mol}{236.31 g}* \frac{.250 g}{1}=1.1 \times 10^{-3} mol = 1.1 \ mmol$$