Answer
$$1.16*10^{21}$$
Work Step by Step
We find:
$$ \frac{.0599 g}{1} \frac{1 mol}{30.97 g} \frac{6.022*10^{23} molecules}{mol}=1.16*10^{21}$$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 77d
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