Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 83a


1.4 mmol

Work Step by Step

We know that the given compound has a molar mass of 183.19 g/mol. Since we also know that there is .250 grams present in the sample, we obtain: $$\frac{1 mol}{183.19 g}* \frac{.250 g}{1}=1.4 \times 10^{-3} mol = 1.4 \ mmol $$
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