Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 74


$ 4.131\times10^{23}\,Cr\,atoms$

Work Step by Step

$35.67\,g\,Cr=$ $35.67\,g\,Cr\times\frac{1\,mol\,Cr}{51.9961\,g\,Cr}\times\frac{6.022\times10^{23}\,Cr\,atoms}{1\,mol\,Cr}$ $=4.131\times10^{23}\,Cr\,atoms$
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