Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 84b


.035 mol

Work Step by Step

We compute the molar mass using the number of each type of atom present and the molar mass of each element present: 8(12.01 g/mol) + 9(1.01 g/mol) + 2(16.01 g/mol) + 1(14.01g/mol) This gives: 151.16 g/mol We now find the number of moles present in the sample: $$\frac{5.32g}{1} \frac{mol}{151.16 g} = .035\ mol$$
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