Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 77c


.06 g

Work Step by Step

We find: $$ \frac{250*10^{-3} g}{1} \frac{mol \ molecules}{387.31 g} \frac{3 \ mol \ P}{mol \ molecules} \frac{30.97 g}{mol \ P} = .06 g$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.