Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Topical Questions - Page 90d: 85b


$$1.08*10^{21} molecules$$

Work Step by Step

We use conversions to find: $$ \frac{.324 g}{1}* \frac{1 mol}{180.15 g}* \frac{6.022*10^{23} molecules}{mol}\\ =1.08*10^{21} molecules$$
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