Answer
See answer below.
Work Step by Step
a) Water and carbon dioxide.
b) $CH_4+2\ O_2\rightarrow CO_2+2\ H_2O$
c) Number of moles of methane:
$25.5\ g\div 16.04\ g/mol=1.59\ mol$
From stoichiometry:
$1.59\ mol\times2/1\times 32.00\ g/mol\ Fe=101.7\ g\ O_2$
d) The same as the reactants:
$25.5\ g+101.7\ g=127.2\ g$
