## Chemistry and Chemical Reactivity (9th Edition)

$3.75\ mol\ O_2$ $2.5\ mol\ PbO$ $2.5\ mol\ SO_2$
From stoichiometry: $2.5\ mol\times3_{O_2}/2_{PbS}=3.75\ mol\ O_2$ $2.5\ mol\times2_{PbO}/2_{PbS}=2.5\ mol\ PbO$ $2.5\ mol\times2_{SO_2}/2_{PbS}=2.5\ mol\ SO_2$