Answer
6.0 moles of Al
$335.07\ g$
Work Step by Step
From stoichiometry:
$3.0\ mol\ Fe_2O_3\times2\ mol\ Al/1\ mol\ Fe_2O_3=6.0\ mol\ Al$
$3.0\ mol\ Fe_2O_3\times2\ mol\ Fe/1\ mol\ Fe_2O_3\times 55.845\ g/mol\ Fe=335.07\ g$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179a: 1
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