Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions: 9

Answer

a) $2\ Cr + 3/2\ O_2\rightarrow Cr_2O_3$ b) $0.256\ g\ Cr_2O_3$ c)$0.081\ g\ O_2$

Work Step by Step

a) $2\ Cr + 3/2\ O_2\rightarrow Cr_2O_3$ b) Number of moles of metal: $0.175\ g\div 51.996\ g/mol=0.00337\ mol$ From stoichiometry: $0.00337\ mol\times 1_{Cr_2O_3}/2_{Cr}\times 151.99\ g/mol\ Cr_2O_3=0.256\ g\ Cr_2O_3$ c)From stoichiometry: $0.00337\ mol\times 1.5_{O_2}/2_{Cr}\times 32.00\ g/mol\ O_2=0.081\ g\ O_2$
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