Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179a: 4


a)$317.5\ g\ Fe$ b) $238.6\ g\ CO$

Work Step by Step

a) Number of moles of oxide: $454\ g\div159.688\ g/mol=2.84\ mol$ From stoichiometry: $2.84\ mol\times2/1\times55.845\ g/mol\ Fe=317.5\ g\ Fe$ b) From stoichiometry: $2.84\ mol\times3/1\times 28.01\ g/mol\ CO=238.6\ g\ CO$
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