## Chemistry and Chemical Reactivity (9th Edition)

a)$317.5\ g\ Fe$ b) $238.6\ g\ CO$
a) Number of moles of oxide: $454\ g\div159.688\ g/mol=2.84\ mol$ From stoichiometry: $2.84\ mol\times2/1\times55.845\ g/mol\ Fe=317.5\ g\ Fe$ b) From stoichiometry: $2.84\ mol\times3/1\times 28.01\ g/mol\ CO=238.6\ g\ CO$