Answer
See answer below.
Work Step by Step
a) Water and carbon dioxide
b) $C_2H_6 + 7/2\ O_2\rightarrow 2\ CO_2+3\ H_2O$
c) Number of moles of ethane:
$13.6\ g\div 30.07\ g/mol=0.452\ mol$
From stoichiometry:
$0.452\ mol\times 3.5_{O_2}/1_{C_2H_6}\times 32.00\ g/mol\ O_2=50.66\ g\ O_2$
d)The sum of the mass of the reactants:
$13.6\ g+50.66\ g=64.3\ g$
