Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179a: 3

Answer

$22.74\ g\ Br_2$ $25.31\ g\ Al_2Br_6$

Work Step by Step

Number of moles of aluminum: $2.56\ g\div26.982\ g/mol=0.0949\ mol$ From stoichiometry: $0.0949\ mol\times3/2\times159.808\ g/mol\ Br_2=22.74\ g\ Br_2$ $0.0949\ mol\times1/2\times 533.387\ g/mol\ Al_2Br_6=25.31\ g\ Al_2Br_6$
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