Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions: 2

Answer

$0.0288\ mol\ HCl$ $0.520\ g$

Work Step by Step

Number of moles of hydroxide: $0.750\ g\div78.00\ g/mol=0.00962\ mol$ From stoichiometry: $0.00962\ mol\times3/1=0.0288\ mol\ HCl$ $0.00962\ mol\times3/1\times 18.015\ g/mol\ H_2O=0.520\ g$
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