Answer
$$6CO_2(g) + 6H_2O(l) \longrightarrow C_6H_{12}O_6(aq) + 6O_2(g) $$
Work Step by Step
1. Identify the chemical compounds:
Gaseous carbon dioxide: $CO_2(g)$
Liquid water: $H_2O(l)$
Glucose: $C_6H_{12}O_6(aq)$
Oxygen gas: $O_2(g)$
2. Write the unbalanced reaction.
$$CO_2(g) + H_2O(l) \longrightarrow C_6H_{12}O_6(aq) + O_2(g) $$
- Balance the number of carbon atoms:
$$6CO_2(g) + H_2O(l) \longrightarrow C_6H_{12}O_6(aq) + O_2(g) $$
- Balance the number of hydrogen atoms:
$$6CO_2(g) + 6H_2O(l) \longrightarrow C_6H_{12}O_6(aq) + O_2(g) $$
- Balance the number of oxygen atoms:
$$6CO_2(g) + 6H_2O(l) \longrightarrow C_6H_{12}O_6(aq) + 6O_2(g) $$
