Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 133: 94c

Answer

$C_{18}H_{12}N_{6}$

Work Step by Step

Calculate the molar mass of the empirical formula by adding the molar masses of its constituent elements together. $3(12.01)+2(1.01)+1(14.0)= 52.05$ Divide the molar mass given by this number and round to the nearest whole number (it should be really close). $\frac{312.29}{52.05}=6$ Multiply the Empirical formula by this number to get the molecular formula. $6(C_{3}H_{2}N)=C_{18}H_{12}N_{6}$
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