Answer
$C_{6}H_{3}Cl_{3}$
Work Step by Step
Calculate the molar mass of the empirical formula by adding the molar masses of its constituent elements together.
$2(12.01)+1(1.01)+1(35.45)= 60.48$
Divide the molar mass given by this number and round to the nearest whole number (it should be really close).
$\frac{181.44}{60.48}=3$
Multiply the Empirical formula by this number to get the molecular formula.
$3(C_{2}HCl)=C_{6}H_{3}Cl_{3}$
