Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 133: 93a

Answer

$C_{12}H_{14}N_{2}$

Work Step by Step

Calculate the molar mass of the empirical formula by adding the molar masses of its constituent elements together. $6(12.01)+7(1.01)+1(14.0)=93.13$ Divide the molar mass given by this number. $\frac{186.24}{93.13}=2$ Multiply the empirical formula by this number to get the molecular formula. $2(C_{6}H_{7}N)=C_{12}H_{14}N_{2}$
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