Answer
The balanced chemical equation is :
$PbS(s) + 2 HBr(aq) \rightarrow PbBr_2(s) + H_2S(g)$
Work Step by Step
Solid lead(II) sulfide $(PbS)$ and aqueous hydrobromic acid $(HBr)$ are the reactants.
Solid lead(II) bromide $(PbBr_2)$ and dihydrogen monosulfide $(H_2S)$ gas are the products.
The balance chemical equation for this reaction is:
$PbS(s) + 2 HBr(aq) \rightarrow PbBr_2(s) + H_2S(g)$
