Answer
$3N_{2}H_{4}(l)\ \rightarrow 4NH_{3}(g)+N_{2}(g)$
Work Step by Step
Add a coefficient of 3 to $N_{2}H_{4}$ and a coefficient of 4 to $NH_{3}$ so that each side has 6 $N$ and 12 $H$.
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 134: 110b
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