Answer
$$3KOH(aq) + FeCl_3(aq) \longrightarrow Fe(OH)_3(s) + 3KCl(aq)$$
Work Step by Step
1. Identify the compounds:
Aqueous potassium hydroxide: $KOH(aq)$
Aqueous iron (III) chloride: $FeCl_3(aq)$
Solid iron (III) hydroxide: $Fe(OH)_3(s)$
Aqueous potassium chloride: $KCl(aq)$
2. Write the unbalanced reaction, and balance it:
$$KOH(aq) + FeCl_3(aq) \longrightarrow Fe(OH)_3(s) + KCl(aq)$$
- Balance the number of Oxygen atoms:
$$3KOH(aq) + FeCl_3(aq) \longrightarrow Fe(OH)_3(s) + KCl(aq)$$
- Balance the number of Potassium atoms:
$$3KOH(aq) + FeCl_3(aq) \longrightarrow Fe(OH)_3(s) + 3KCl(aq)$$
