Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 3 - Mass Relationships in Chemical Reactions - Section Problems - Page 106: 53


There are $ 5 \times 10^{18}\ atoms$ of carbon in the period.

Work Step by Step

1. Determine the molar mass of $carbon$: Molar mass = Molecular weight value = 12.01 $g/mol$ $(C)$ 2. Calculate the number of moles and the number of atoms: $0.0001$ $g \times \frac{1 mol (C)}{12.01g (C)} \times \frac{6.022 \times 10^{23} atoms(C)}{1 mol (C)}= 5 \times 10^{18} atoms (C)$
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