## Chemistry (7th Edition)

(a) $2NH_4NO_3 --\gt 2N_2 + O_2 + 4H_2O$ (b) $C_2H_6O + O_2 -- \gt C_2H_4O_2 + H_2O$ (c) $C_2H_8N_2 + 2N_2O_4 -- \gt 3N_2 + 2CO_2 + 4H_2O$
(a) $NH_4NO_3 --\gt N_2 + O_2 + H_2O$ Balance the hydrogen on each side: $NH_4NO_3 --\gt N_2 + O_2 + 2H_2O$ Now, we would need only one oxygen from the $O_2$ to balance. $NH_4NO_3 --\gt N_2 + \frac{1}{2}O_2 + 2H_2O$ Multiply the coefficients by 2 $2NH_4NO_3 --\gt 2N_2 + O_2 + 4H_2O$ (b) $C_2H_6O + O_2 -- \gt C_2H_4O_2 + H_2O$ The equation is already balanced. (c) $C_2H_8N_2 + N_2O_4 -- \gt N_2 + CO_2 + H_2O$ Balance the carbon compounds on each side: $C_2H_8N_2 + N_2O_4 -- \gt N_2 + 2CO_2 + H_2O$ Balance the hydrogen compounds on each side: $C_2H_8N_2 + N_2O_4 -- \gt N_2 + 2CO_2 + 4H_2O$ Balance the oxygen compounds on each side: $C_2H_8N_2 + 2N_2O_4 -- \gt N_2 + 2CO_2 + 4H_2O$ Finish by balancing the nitrogen compounds on each side: $C_2H_8N_2 + 2N_2O_4 -- \gt 3N_2 + 2CO_2 + 4H_2O$