Answer
(a) $2NH_4NO_3 --\gt 2N_2 + O_2 + 4H_2O$
(b) $C_2H_6O + O_2 -- \gt C_2H_4O_2 + H_2O$
(c) $C_2H_8N_2 + 2N_2O_4 -- \gt 3N_2 + 2CO_2 + 4H_2O$
Work Step by Step
(a)
$NH_4NO_3 --\gt N_2 + O_2 + H_2O$
Balance the hydrogen on each side:
$NH_4NO_3 --\gt N_2 + O_2 + 2H_2O$
Now, we would need only one oxygen from the $O_2$ to balance.
$NH_4NO_3 --\gt N_2 + \frac{1}{2}O_2 + 2H_2O$
Multiply the coefficients by 2
$2NH_4NO_3 --\gt 2N_2 + O_2 + 4H_2O$
(b)
$C_2H_6O + O_2 -- \gt C_2H_4O_2 + H_2O$
The equation is already balanced.
(c)
$C_2H_8N_2 + N_2O_4 -- \gt N_2 + CO_2 + H_2O$
Balance the carbon compounds on each side:
$C_2H_8N_2 + N_2O_4 -- \gt N_2 + 2CO_2 + H_2O$
Balance the hydrogen compounds on each side:
$C_2H_8N_2 + N_2O_4 -- \gt N_2 + 2CO_2 + 4H_2O$
Balance the oxygen compounds on each side:
$C_2H_8N_2 + 2N_2O_4 -- \gt N_2 + 2CO_2 + 4H_2O$
Finish by balancing the nitrogen compounds on each side:
$C_2H_8N_2 + 2N_2O_4 -- \gt 3N_2 + 2CO_2 + 4H_2O$
