Answer
(a) $0.019$ mol(Cr).
(b) $0.014$ mol(Cl)
(c) $0.0051$ mol(Au).
(d) $0.059$ mol(NH_3).
Work Step by Step
(a) Molar mass (Cr) = Molecular weight value (Cr) = 51.996 g/mol
$1.0$ $g $ $(Cr)$ $\times \frac{1 mol(Cr)}{51.996g(Cr)} = 0.019$ mol(Cr).
(b) Molar mass ($Cl$): 35.45
$Cl_2 : Cl * 2 = 35.45 * 2 = 70.90$ g/mol
$1.0$ $g $ $(Cl)$ $\times \frac{1 mol(Cl)}{70.90g(Cl)} = 0.014$ mol(Cl).
(c) Molar mass (Au): 196.97 g/mol.
$1.0$ $g $ $(Au)$ $\times \frac{1 mol(Au)}{196.97g(Au)} = 0.0051$ mol(Au).
(d) Molar mass (N): 14.01 g/mol; Molar mass (H): 1.01 g/mol.
$NH_3 = N + 3H = 14.01 + 3*1.01 = 17.04$ g/mol
$1.0$ $g $ $(NH_3)$ $\times \frac{1 mol(NH_3)}{17.04g(NH_3)} = 0.059$ mol(NH_3).
