Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 3 - Mass Relationships in Chemical Reactions - Section Problems - Page 106: 40

Answer

(a) $SiCl_4 + 2H_2O -- \gt SiO_2 + 4HCl$ (b) $P_4O_{10} + 6H_2O -- \gt 4H_3PO_4$ (c) $CaCN_2 + 3H_2O -- \gt CaCO_3 + 2NH_3$ (d) $3NO_2 + H_2O -- \gt 2HNO_3 + NO$

Work Step by Step

(a) Balance the $Cl$ compounds on each side: $SiCl_4 + H_2O -- \gt SiO_2 + 4HCl$ Balance the hydrogen compounds: $SiCl_4 + 2H_2O -- \gt SiO_2 + 4HCl$ (b) Balance the $P$ compounds on each side: $P_4O_{10} + H_2O -- \gt 4H_3PO_4$ Balance the $H$ compounds on each side: $P_4O_{10} + 6H_2O -- \gt 4H_3PO_4$ (c) Balance the $N$ compounds on each side: $CaCN_2 + H_2O -- \gt CaCO_3 + 2NH_3$ Balance the $H$ compounds: $CaCN_2 + 3H_2O -- \gt CaCO_3 + 2NH_3$ (d) Balance the $H$ compounds on each side: $NO_2 + H_2O -- \gt 2HNO_3 + NO$ To balance the equation, we just need 2 more $N$ and 4 more oxygens on the left side; therefore, we can just add 2 more $NO_2$. $3NO_2 + H_2O -- \gt 2HNO_3 + NO$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.