Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 3 - Mass Relationships in Chemical Reactions - Section Problems - Page 106: 46


(a) 47.87 g. (b) 159.8 g. (c) 200.59 g. (d) 18.0 g.

Work Step by Step

For (a) and (c): Use the value given on the periodic table for the element. (b) According to the periodic table, the mass of each mole of bromine is equal to 79.9 g. Since we have 2: Mass = $79.9$ g $\times 2 = 159.8$ g. (d) Molar mass for each hydrogen: $1.0$ g/mol, for each oxygen: $16.0$ g/mol Mass = $(1.0*2 + 16.0)$ g = $18.0$ g.
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