# Chapter 3 - Mass Relationships in Chemical Reactions - Section Problems - Page 106: 48

There are 0.867 moles of ions in 27.5 g of $MgCl_2$.

#### Work Step by Step

1. Calculate the molar mass $(MgCl_2)$: 24.31* 1 + 35.45* 2 = 95.21 g/mol 2. Calculate the number of moles $(MgCl_2)$: $n(moles) = \frac{mass(g)}{mm(g/mol)}$ $n(moles) = \frac{ 27.5}{ 95.21}$ $n(moles) = 0.289$ 3. Each $MgCl_2$ has 1 $Mg^{2+}$ ion and 2 $Cl^-$ ions; therefore, there are a total of 3 ions. $0.289 mol (MgCl_2) \times \frac{3 ions}{1 MgCl_2} = 0.867\ mol\ of \ ions$

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