## Chemistry (7th Edition)

Published by Pearson

# Chapter 3 - Mass Relationships in Chemical Reactions - Section Problems - Page 106: 42

#### Answer

(a) $472.08$ $u$ (b) 88.10 $u$ (c) 120.91 $u$

#### Work Step by Step

(a) Molecular weight ($Hg_2Cl_2$): 200.59* 2 + 35.45* 2 = 472.08 $u$ (b) Molecular weight ($C_4H_8O_2$): 12.01* 4 + 1.008* 8 + 16.00* 2 = 88.10 g/mol (c) Molecular weight ($CF_2Cl_2$): 12.01* 1 + 19.00* 2 + 35.45* 2 = 120.91 g/mol

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