Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 400: 47c

$x = (88~cos~50.0^{\circ})~t$ $y = (88~sin~50.0^{\circ})~t-16~t^2$

From part (b), we know that $\theta = 50.0^{\circ}$ We can write an equation for $x$: $x = (v~cos~\theta)~t$ $x = (88~cos~50.0^{\circ})~t$ We can write an equation for $y$: $y = (v~sin~\theta)~t-16~t^2$ $y = (88~sin~50.0^{\circ})~t-16~t^2$