Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 400: 47a

Answer

$x = 56.56530965~t$ $y = -16~t^2+67.41191099~t$ We can see the graph below:

Work Step by Step

$x = 56.56530965~t$ $y = -16~t^2+67.41191099~t$ When t = 0: $x = 56.56530965~(0) = 0$ $y = -16~(0)^2+67.41191099~(0) = 0$ When t = 1: $x = 56.56530965~(1) = 56.56530965$ $y = -16~(1)^2+67.41191099~(1) = 51.41191099$ When t = 2: $x = 56.56530965~(2) = 113.1306193$ $y = -16~(2)^2+67.41191099~(2) = 70.82382198$ When t = 3: $x = 56.56530965~(3) = 169.69592895$ $y = -16~(3)^2+67.41191099~(3) = 58.23573297$ When t = 4: $x = 56.56530965~(4) = 226.2612386$ $y = -16~(4)^2+67.41191099~(4) = 13.64764396$ We can see the graph below:
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