Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 400: 46a

Answer

$x = 82.69295063~t$ $y = -16~t^2+30.09777261~t$ We can see the graph below:

Work Step by Step

$x = 82.69295063~t$ $y = -16~t^2+30.09777261~t$ When t = 0: $x = 82.69295063~(0) = 0$ $y = -16~(0)^2+30.09777261~(0) = 0$ When t = 0.5: $x = 82.69295063~(0.5) = 41.346475315$ $y = -16~(0.5)^2+30.09777261~(0.5) = 11.048886305$ When t = 1: $x = 82.69295063~(1) = 82.69295063$ $y = -16~(1)^2+30.09777261~(1) = 14.09777261$ When t = 1.5: $x = 82.69295063~(1.5) = 124.039425945$ $y = -16~(1.5)^2+30.09777261~(1.5) = 9.146658915$ When t = 1.8: $x = 82.69295063~(1.8) = 148.847311134$ $y = -16~(1.8)^2+30.09777261~(1.8) = 2.335990698$ We can see the graph below:
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.