Answer
$P(E~|~F)=0.2333$
Work Step by Step
$P(E~and~F)=0.105$
Using the Conditional Probability Rule (page 288):
$P(E~|~F)=\frac{P(E~and~F)}{P(F)}=\frac{0.105}{0.45}=0.2333$
Statistics: Informed Decisions Using Data (4th Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0321757270
ISBN 13:
978-0-32175-727-2
Chapter 5 - Review - Test - Page 317: 6c
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