Answer
$P(2~|~female)=\frac{87}{188}\approx0.4628$
Work Step by Step
According to the marginal distribution (see page 235) of the first row: $N(female)=188$
According to the cell in the first row, third column: $N(female~and~2)=87$
Using the Conditional Probability Rule (page 288):
$P(2~|~female)=\frac{N(female~and~2)}{N(female)}=\frac{87}{188}\approx0.4628$
