Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Review - Test - Page 317: 6b

Answer

$P(E~or~F)=0.495$

Work Step by Step

$P(E~and~F)=0.105$ Using the General Addition Rule (page 273): $P(E~or~F)=P(E)+P(F)-P(E~and~F)=0.15+0.45-0.105=0.495$
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