Answer
$P(male~|~4)=\frac{2}{9}\approx0.2222$
Work Step by Step
According to the marginal distribution (see page 235) of the fifth column: $N(4)=36$
According to the cell in the second row, fifth column: $N(male~and~4)=8$
Using the Conditional Probability Rule (page 288):
$P(male~|~4)=\frac{N(male~and~4)}{N(4)}=\frac{8}{36}=\frac{2}{9}\approx0.2222$
