Statistics: Informed Decisions Using Data (4th Edition)

Published by Pearson
ISBN 10: 0321757270
ISBN 13: 978-0-32175-727-2

Chapter 5 - Review - Test - Page 317: 9

Answer

$P(was~in~a~structure)=0.32$ $P(was~not~in~a~structure)=0.68$

Work Step by Step

$32$% $=0.32$ $P(was~in~a~structure)=0.32$ The event "was not in a structure" is the complement of "was in a structure". Using the Complement Rule (see page 275): $P(was~not~in~a~structure)=1-P(was~in~a~structure)=1-0.32=0.68$
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