Answer
$P(win~seven~games~in~a~row)=0.58^7\approx0.02208$
Work Step by Step
$58$% $=0.58$
$P(win~a~game)=0.58$
Using the Multiplication Rule for Independent Events (page 282):
$P(win~seven~games~in~a~row)=P(win~a~game)\times P(win~a~game)\times P(win~a~game)\times P(win~a~game)\times P(win~a~game)\times P(win~a~game)\times P(win~a~game)=[ P(win~a~game)]^7=0.58^7\approx0.02208$
