Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.3 - Double-Angle, Half-Angle, and Product-Sum Formulas - 7.3 Exercises - Page 561: 47

Answer

$\frac{336}{625}$

Work Step by Step

Let $cos^{-1}\frac{7}{25}=y$, we have $cos(y)=\frac{7}{25}, sin(y)=\frac{24}{25},$ and $sin(2cos^{-1}\frac{7}{25})=sin(2y) =2sin(y)cos(y)=\frac{336}{625}$
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