Answer
a. $\cos \theta$
b. $\sin \theta$
Work Step by Step
a. Use the formula $\cos 2x=\cos^2 x-\sin^2 x$ with $x=\frac{\theta}{2}$. Then $\cos^2 \frac{\theta}{2}-\sin^2\frac{\theta}{2}=\cos(2*\frac{\theta}{2})=\cos \theta$.
b. Use the formula $\sin 2x=2\sin x\cos x$ with $x=\frac{\theta}{2}$. Then $2\sin \frac{\theta}{2}\cos \frac{\theta}{2}=\sin(2*\frac{\theta}{2})=\sin \theta$.