Chapter 7 - Section 7.3 - Double-Angle, Half-Angle, and Product-Sum Formulas - 7.3 Exercises - Page 561: 10

$sin2x=\frac{12}{13}$ $cos2x=-\frac{5}{13}$ $tan2x=-\frac{12}{5}$

$tan(x)=\frac{3}{2}, sin(x)=\frac{3\sqrt {13}}{13}, cos(x)=\frac{2\sqrt {13}}{13}$ $sin2x=2sin(x)cos(x)=\frac{12}{13}$ $cos2x=2cos^2x-1=-\frac{5}{13}$ $tan2x=\frac{sin2x}{cos2x}=-\frac{12}{5}$