Answer
$\sqrt{2}-1$
Work Step by Step
Use the half-angle formula, $\tan\frac{u}{2}=\frac{1-\cos u}{\sin u}$.
$\tan 22.5^\circ$
$=\tan \frac{45^\circ}{2}$
$=\frac{1-\cos 45^\circ}{\sin 45^\circ}$
$=\frac{1-\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}}$
$=\frac{(1-\frac{\sqrt{2}}{2})\frac{2}{\sqrt{2}}}{\frac{\sqrt{2}}{2}*\frac{2}{\sqrt{2}}}$
$=\frac{\frac{2}{\sqrt{2}}-1}{1}$
$=\sqrt{2}-1$