Chapter 7 - Section 7.3 - Double-Angle, Half-Angle, and Product-Sum Formulas - 7.3 Exercises - Page 561: 3

$120/169$

We know that by the trigonometric identity $sin^2(x)+cos^2(x)=1$ that $cos(x) = \sqrt {1-(5/12)^2}$ or cos(x) is 12/13. Thus we use the identity $sin(2x)=2sin(x)cos(x)$ and get $sin(2x)=2\times12\times5/13^2$ or 60/169.