## Precalculus: Mathematics for Calculus, 7th Edition

$120/169$
We know that by the trigonometric identity $sin^2(x)+cos^2(x)=1$ that $cos(x) = \sqrt {1-(5/12)^2}$ or cos(x) is 12/13. Thus we use the identity $sin(2x)=2sin(x)cos(x)$ and get $sin(2x)=2\times12\times5/13^2$ or 60/169.