Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.2 - Addition and Subtraction Formulas - 7.2 Exercises - Page 551: 4

Answer

sin(15) = $\frac{\sqrt 6 - \sqrt 2 }{4}$

Work Step by Step

1. sin 15 = sin(45-30) 2. Use the formula for difference of sins: sin(x-y)=(sinx)(cosy)-(cosx)(siny) 3. Plug in values: sin(45-30) = sin45cos30-cos45sin30 4. sin(45-30) = $\frac{\sqrt 6}{4} - \frac{\sqrt 2}{4}$ 5. sin(45-30) = $\frac{\sqrt 6 - \sqrt 2 }{4}$ 6. sin(15) = $\frac{\sqrt 6 - \sqrt 2 }{4}$
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